Help calculating mass and escape velocity |
Help calculating mass and escape velocity |
Jan 21 2008, 07:47 PM
Post
#1
|
|
Newbie Group: Members Posts: 5 Joined: 21-January 08 Member No.: 4022 |
If you have a kuiper belt object with say a diameter of 48km and assume a density of 1.5 gm/cm^3, how do you find the mass and escape velocity?
Sorry if this sounds elementary, I am just trying to learn. I think that the surface area would be 7,238km^2 (4pi(r^2)) and that the volume would be 57,905km^3 ((4/3)*pi*r^3). I seem to start getting into trouble solving for the mass (given that density = mass/volume.) Would the mass only be 1.5 * 57,905,000m^3 = 86,857,500m^3 = 86,857.5 kg? What would the escape velocity be? |
|
|
Jan 21 2008, 08:03 PM
Post
#2
|
|
Senior Member Group: Members Posts: 1018 Joined: 29-November 05 From: Seattle, WA, USA Member No.: 590 |
I guess we're assuming this KBO is a sphere. :-)
The surface and volume calculations are correct; you get into trouble trying to use your density (which is g/cm^3) with your volume (which is km^3). Also, although there are 1,000 m in a km, there are 1,000,000 m^2 in a km^2 and 1,000,000,000 m^3 in a km^3. Since your density is in cm^3, you'll need to go from km^3 to cm^3 before you can multiply it by the density, and your result will be grams. Escape velocity is sqrt(2MG/r) where M is the mass of the KBO, G is the gravitational constant, and r is the radius. You cannot derive this formula without Calculus, but if you do know Calculus, it's not hard. Again, you'll need to get the gravitational constant into the same sort of units as you're using for M and r. Hope that helps. So is this for a class, or just your own curiosity? :-) --Greg |
|
|
Jan 21 2008, 09:50 PM
Post
#3
|
|
Newbie Group: Members Posts: 5 Joined: 21-January 08 Member No.: 4022 |
I guess we're assuming this KBO is a sphere. :-) The surface and volume calculations are correct; you get into trouble trying to use your density (which is g/cm^3) with your volume (which is km^3). Also, although there are 1,000 m in a km, there are 1,000,000 m^2 in a km^2 and 1,000,000,000 m^3 in a km^3. Since your density is in cm^3, you'll need to go from km^3 to cm^3 before you can multiply it by the density, and your result will be grams. Escape velocity is sqrt(2MG/r) where M is the mass of the KBO, G is the gravitational constant, and r is the radius. You cannot derive this formula without Calculus, but if you do know Calculus, it's not hard. Again, you'll need to get the gravitational constant into the same sort of units as you're using for M and r. Hope that helps. So is this for a class, or just your own curiosity? :-) --Greg Hi Greg; I am a freshman in high school, so no calculus yet. So if I am doing the mass calculation correctly: Given a basically spherical KBO that is 48km in diameter with an assumed density of 1.5 gm/cm^3 and thus volume = 57,905km^3; Mass = 1.5 * 57,905km^3 = 86,857.5km^3. (km^3 conversion: 1000^3 = 10^9m; Further conversion to cm = another 10^2) so the mass = 8.68575 x 10^15kg? (9+2+4) or am I still off by a factor of 10-1000? Help! |
|
|
Lo-Fi Version | Time is now: 19th June 2024 - 03:09 PM |
RULES AND GUIDELINES Please read the Forum Rules and Guidelines before posting. IMAGE COPYRIGHT |
OPINIONS AND MODERATION Opinions expressed on UnmannedSpaceflight.com are those of the individual posters and do not necessarily reflect the opinions of UnmannedSpaceflight.com or The Planetary Society. The all-volunteer UnmannedSpaceflight.com moderation team is wholly independent of The Planetary Society. The Planetary Society has no influence over decisions made by the UnmannedSpaceflight.com moderators. |
SUPPORT THE FORUM Unmannedspaceflight.com is funded by the Planetary Society. Please consider supporting our work and many other projects by donating to the Society or becoming a member. |