My Assistant
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Out Of The Crater At Last. |
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Mar 25 2004, 09:19 AM
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#16
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Guests |
A new view of the rock hit by the aribags:
http://marsrovers.jpl.nasa.gov/gallery/all...30P2557L7M1.JPG http://marsrovers.jpl.nasa.gov/gallery/all...30P2557R1M1.JPG How far away is it and how large?? |
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Mar 25 2004, 03:51 PM
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#17
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![]() Senior Member ![]() ![]() ![]() ![]() Group: Members Posts: 1465 Joined: 9-February 04 From: Columbus OH USA Member No.: 13 |
>How far away is it and how large??
Based on the left and right images, there's a parallax of 92 pixels at the rock. The distance equation for Opportunity's pancam is: D = 1071/(130 - N) D = 1071/(130 - 92) = 28.2 meters The width of the rock is 54 pixels. At 0.28 mrad/pixel (pancam spec) that's 15 mrad. Width then would be 28.2*0.015 = 0.42 m. The width of the bounce mark is 223 pixels or 1.8 m. Joe -------------------- |
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Mar 25 2004, 04:16 PM
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#18
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Founder ![]() ![]() ![]() ![]() Group: Chairman Posts: 14445 Joined: 8-February 04 Member No.: 1 |
QUOTE (jmknapp @ Mar 25 2004, 03:51 PM) 28.2 meters 1 days rove. We need some sort of applet or little VB app to do those sums for us Doug |
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Mar 25 2004, 08:10 PM
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#19
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![]() Senior Member ![]() ![]() ![]() ![]() Group: Members Posts: 1465 Joined: 9-February 04 From: Columbus OH USA Member No.: 13 |
>We need some sort of applet or little VB app to do those sums for us
OK, I'll do a little forms-based web page, probably tomorrow (engaged rest of today). Even with such a calculator, the main work is downloading the two pictures and reading them into an image processing program to get the pixel locations. -------------------- |
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Mar 28 2004, 09:03 PM
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#20
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![]() Senior Member ![]() ![]() ![]() ![]() Group: Members Posts: 1465 Joined: 9-February 04 From: Columbus OH USA Member No.: 13 |
OK, here's a bare-bones web-based stereoscopic range calculator for the MERs:
>>MER Parallax Calculator<< What you have to do is from a l/r stereo pair (EFF) from the pancam or navcam, identify an object you want to calculate the range to. That object should have a small feature on it that you can locate down to the accuracy of one pixel. Then input the horizontal position of this feature in the left and right images. If desired, input an object dimension in pixels (e.g. width). -------------------- |
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Mar 28 2004, 09:13 PM
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#21
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Founder ![]() ![]() ![]() ![]() Group: Chairman Posts: 14445 Joined: 8-February 04 Member No.: 1 |
great stuff
Doug |
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